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4. Types of chemical reactions and solution stoichiometry

Solutions

solution: solute and solvent
solute: what is dissolved
solvent: what does the dissolving
looks like the solvent
mixtures
heterogenous: two (or more) things mixed together that look like two (or more) things
homogenous: two (or more) things mixed together that look like one thing
examples
solid solute and liquid solvent: salt water
liquid solute and liquid solvent: juice
gas solute and liquid solvent: soda
solid solute and solid solvent: alloy
gas solute and gas solvent: air
gas solute and solid solvent: foam
liquid solute and solid solvent: fillings

Electrolytes

electrolyte: solution that conducts electricity
strong electrolyte: ionic compound that is completely dissolved; conducts electricity well
weak electrolyte: compound that is partially dissolved; conducts electricity poorly
nonelectrolyte: covalent compound; does not conduct electricity

Molarity and dilutions

way to measure concentration of a solution
example: calculate the molarity of 11.5 g of NaOH in enough water to make 1.50 L of solution
example: convert above to only Na
dilution: when you make a solution less concentrated (add more solvent)
M: molarity
V: volume
1: at start
2: after dilution
example: what volume of 16 M sulfuric acid must be used to make 1.5 L of a 0.10 M solution?
(16 M)(V₁) = (0.10 M)(1.5 L)
V₁ = 9.4 × 10⁻³ L

Creating solutions

get a volumetric flask
add solute to flask
add half the amount of solvent
put on the stopper
mix until the solute dissolves
fill with solvent up to the fill line
mix again

Spectroscopy

image.png
spectroscopy: an experiment that uses lightwaves to determine concentration
absorbance: measurement of how much light gets stopped/absorbed

Beer-Lambert Law

A = abC
A: absorbance
C: concentration
ab: constant
standard: a bunch of known values that help you determine an unknown
Beer-Lambert Law uses standards to make a graph
graphing
A = abC; y = mx + b
A = y
C = x
m = ab
0 = b
y-axis: absorbance
x-axis: concentration (M)
image.png

Saturation

saturated: when a solvent can no longer dissolve a solute
unsaturated: solvent can dissolve more
increasing solvent dissolving
change the temperature of the solvent (mostly increase in temperature)
add more solvent
mix the solvent
increase the surface area of the solute

Types of reactions

Precipitation

precipitation reaction: two aqueous solutions are mixed; precipitate (solid) forms
solubility rules (order matters)
sodium (Na⁺), potassium (K⁺), ammonium (NH₄⁺) compounds are always soluble
nitrates (NO₃⁻), acetates, chlorates are always soluble
most chlorides are soluble
except silver, mercury (I), lead
lead (II) chloride is soluble in hot water
most sulfates are soluble
except those of barium, strontium, lead, calcium, mercury
most carbonates, phosphates, silicates are insoluble
except those of sodium, potassium, ammonium
most sulfides are insoluble
except those of calcium, strontium, sodium, potassium, ammonium
example: Na₂SO₄(aq) + Pb(NO₃)₂(aq)
reactants are always aqueous
double replacement reaction: switch
check charges
NaNO₃(aq) + PbSO₄(s)
example: KNO₃ (aq) + BaCl₂ (aq)
KCl + BaNO₃
KCl + Ba(NO₃)₂
KCl(aq) + Ba(NO₃)₂(aq)
no precipitate
net ionic equation: separate every aqueous solution into ions and remove what is the same on both sides or just keep the ions from the solid
example: what is the precipitate and net ionic equation of NaCl(aq) + AgNO₃(aq)
write out entire equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s)
for transition metals, find charge from reactants
AgCl is the precipitate
ionic equation: Na⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + AgCl(s)
net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
spectator ions: ions that did not participate in the reaction; not present in a net ionic equation

Acids and bases

acid
base
usually has an H in the formula
usually has an OH in the formula
pH less than 7
pH greater than 7
sour
bitter
can burn you
can burn you
gives protons
accepts protons
e.g. HCl, vinegar, citric acid
e.g. soap, bleach, NaOH
There are no rows in this table
Arrhenius’s definition
acid: always makes an H⁺ when put into water
base: always makes an OH⁻ when put into water
Brønsted-Lowry definition
acid: donates proton (H⁺)
base: accepts proton (H⁺)
example: HCl + H₂O
acid (HCl) donates H to base (H₂O)
H₃O + Cl⁻
example: NaOH + H₂O
acid (H₂O) donates H to base (NaOH)
OH⁻ + Na⁺ + H₂O
amphoteric: can be an acid or a base
e.g. water
conjugate acid: base becomes an acid
conjugate base: acid becomes a base
example: NH₃ + H₂O
acid (H₂O) donates H to base (NH₃)
NH₄⁺ + OH⁻
NH⁺ is a conjugate acid
OH⁻ is a conjugate base
example: HBr + H₂O
H₃O⁺ + Br⁻
H₃O⁺ is a conjugate acid
Br⁻ is a conjugate base
strong acid: acid that breaks apart completely
HCl
HBr
HI
H₂SO₄
HNO₃
HClO₄
strong base: base that breaks apart completely
if it has OH in the formula
neutralization reaction: acid + base → water + salt (ionic compound)
e.g. HCl + NaOH → H₂O + NaCl
e.g. HBr + LiOH → H₂O + LiBr

Oxidation-reduction

oxidation-reduction reaction: reaction that contains oxygen and/or a transfer of electrons
e.g. rusting, combustion, cellular respiration, photosynthesis, bleaching, batteries
OIL RIG
oxidation: involves loss of electrons
reduction: involves gaining electrons
oxidation numbers: keep track of electrons in a oxidation-reduction reaction
element → 0
monoatomic ion → charge of ion
fluorine → -1
oxygen → -2
peroxide (O₂²⁻) → -1 (only for O—O bonds)
hydrogen → +1
example: CO₂; oxidation number for carbon
oxygen is always -2
2 oxygens → -4
oxidation number for carbon must be +4 to have neutral charge
example: NO₃⁻; oxidation number for nitrogen
oxygens have -6 charge
nitrogen must have +5 charge to have 1- charge
example: 2Na + Cl₂ → 2NaCl; what is oxidized and what is reduced
charges: 2(0) + 0 → 2(+1)(-1)
Na → lost an electron → oxidized
Cl → gained an electron → reduced
example: balance Cu(s) + Ag⁺(aq) → Ag(s) + Cu²⁺(aq)
determine the half-reactions
Cu(s) → Cu²⁺(aq)
Ag⁺(aq) → Ag(s)
add electrons to balance the charges
Cu(s) → Cu²⁺(aq) + 2e⁻
Ag⁺(aq) + e⁻ → Ag(s)
multiply the reaction(s) to make the electrons equal
Cu(s) → Cu²⁺(aq) + 2e⁻
2Ag⁺(aq) + 2e⁻ → 2Ag(s)
combine reactions and cancel
Cu(s) + 2e⁻ + 2Ag⁺(aq) → Cu²⁺(aq) + 2e⁻ + 2Ag(s)
Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s)

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