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Pricing Variations

[ ]
kg
Price As Of:
$ 0
Price Until:
$ 0
Pricing Variations
1
Name
Product
VolumeInKg
Price
pricePerKg
priceAsOf
priceUntil
1
1 | Sand $176.74 per 1,000 kg
Sand
1,000
$176.74
$0.177
1 | Sand $176.74 per 1,000 kg
1 | Sand $176.74 per 1,000 kg
2
2 | Sand $1,060.00 per 10,000 kg
Sand
10,000
$1,060.00
$0.106
1 | Sand $176.74 per 1,000 kg
1 | Sand $176.74 per 1,000 kg
3
3 | Sand $3,990.00 per 50,000 kg
Sand
50,000
$3,990.00
$0.080
1 | Sand $176.74 per 1,000 kg
1 | Sand $176.74 per 1,000 kg
4
4 | Sand $5,000.00 per 70,000 kg
Sand
70,000
$5,000.00
$0.071
1 | Sand $176.74 per 1,000 kg
1 | Sand $176.74 per 1,000 kg
5
5 | Sand $6,900.00 per 100,000 kg
Sand
100,000
$6,900.00
$0.069
1 | Sand $176.74 per 1,000 kg
1 | Sand $176.74 per 1,000 kg
There are no rows in this table
The view below shows how you can rewrite the content living in the table while adding an extra layer of content. The set up of the first list starting with 0001 requires insight in the composition of lists in general. A bit further down the details. You can do this in various ways, like using Sum() instead of +1.
0001 - 1,000 → $176.74
1,001 - 10,000 → $1,060.00
10,001 - 50,000 → $3,990.00
50,001 - 70,000 → $5,000.00
70,001 - 100,000 → $6,900.00

11,00110,00150,00170,001
Sequence(1,[DB Sand].Count()).ForEach(CurrentValue.WithName(Root,
ListCombine(1,Sequence(1,[DB Sand].Count()-1).ForEach([DB Sand].VolumeInKg.Nth(CurrentValue).
Nth(Root)+1))
)).First()

Please note that the writing does not instruct you how to calculate any outcome as written in my blog.
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